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For nucleons, we know that g = (µ * hbar)/(µ_N * I).
For electrons, we have that g = (2mµ)/(eS)(1.a)
g_GS = ((-0,5940) * hbar)/(µ_N * 1/2) = -1,188 hbar/µ_Ng_245keV = ((-0,766) * hbar)/(µ_N * 5/2) = -0,3064 hbar/µ_N
(1.b)
1 Bohr magneton = µ_B = (e * hbar)/(2 * m), so we find
g = ((2 * m) * ((e * hbar)/(2 * m)))/(e * 1/2) = 2 * hbar(1.c)
µ = (g * µ_N * I)/hbar = (-3,826 * µ_N * 1/2)/hbar = -1,913 µ_N/hbar
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