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  • #6343
    Stef Kunnen
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    1.a) µ = g*µ_N*I/hbar
    µ = -0.5940 µ_N
    I = hbar* 1/2

    g = -0.5940*2 = -1.188
    g = -0.766 * 2/5 = -0.3064

    1.b) µ = g*µ_B*S*hbar
    S = 1/2 * hbar
    µ = 1 µ_B

    g*1/2 = 1 <=> g = 2

    1.c) µ = g*µ_n*S/hbar
    S = hbar * 1/2
    g = -3.826

    µ = -3.826/2 µ_n = -1.913

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