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For Cd111 ground state I= 1/2 hbar and magnetic momentis
Mu= -0.5940 * mu_N . With formula Mu = g * mu_N *I/hbar we find that g= mu/mu_N *hbar/I = -0.5940 * 2=-1.188. For 245keV we have g= -0.766 * 2/5 =-0.3064 .Free electron magnetic moment = 1 mu_B
mu_B= e*hbar/2m_e. Bcs electron is free mu= mu_B= g* mu_B *I/hbar —> g= hbar/I = 2Free neutron magnetic moment? g factor is -3.826 with I=1/2
Mu= mu_N * -3.826 * 1/2 = 1.913 (n.m)
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