Home › Forums › Hyperfine course › magnetic hyperfine interaction › in free atoms – task 2 › answer

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  • April 21, 2023 at 11:29 pm #4578
    yury.holubeu
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    We know that a \tilde \mu /(IJ),
    so from the proportion we find that \mu_2=\mu_1 \frac{a_1}{a_2} \frac{I_2}{I_1}

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