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  • #5331
    Jakob Vermeulen
    Participant

    We know that we are only looking at a difference in the nucleus. This means that all factors associated with the electron cloud will cancel out when taking a(1)/a(2). Doing this we then get:

    mu(1) I(2) / mu(2) I(1). We can then isolate mu(2) and then we have:

    mu(2) = mu(1) a(2)I(2)/a(1)I(1)

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