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  • March 5, 2024 at 11:07 pm #5327
    DanteBouckhout
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    a. From mu = g*muN*I /(hbar) we get:
    g = mu*hbar/(mu_N*I)
    which we can fill in with the values -0.5940(3) = mu (GS) and -0.766(3) = mu(245keV) and a spin of 1/2 for GS and 5/2 for 245keV.

    Using the same formula we get
    b. g = 2*hbar*mu_B/mu_N
    c. mu = -3.826*(1/2)*mu_N/hbar

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